Can a xenon run application code without being connected to the cloud and without trying to connect to the cloud? I need to use the SPI, CPU and the I2c and later connect to the cloud when the mesh products become stable and when Blue tooth range is adequate, but I would like to begin hardware design using the mesh devices for the future.
Mesh device charging circuit. The mesh products can run with the Li battery, but the Li will have to be charged when not connected to the PC. Do you apply the external charging voltage to the USB pin? Do PC’s usually have diode protection on the USB to prevent conflicts with other external charging voltages? Presently we use the Electron and I think we charge through the VM pin. No such pin on mesh devices.
Yes, when using a non-AUTOMATIC SYSTEM_MODE
You can connect a USB charger or supply 5V to the VUSB pin.
The docs do feature a block diagram that shows the input power block
What is the
VM pin? Do you mean
On mesh devices
VUSB is the same thing as on Gen1&2 devices
Vin but there is no protection diode between USB and
Vin to prevent back-feeding into the USB port.
There are some posts that address the potential back-feeding and possible workarounds (if needed)
I purchase 3.7V lipo battery with 2 pin JST connector and it fits It is 600mAh far less than 1800mAh that is sold by Particle.io store I looked up the datasheet on xenon and it says the USB port must provide 500mAh however Nothing in connection to wattage requirements for Xenon to power on using the Lipo Battery. I wonder where is the sweet spot for Xenon to power on Somewhere between 3.7V x 1.8AH = 6.66W and 3.7V x 0.5Ah = 1.85W
Ah (Amper x Hour) is not the same as A (Ampere).
Actually no, it would be 1.85Wh - you can’t just drop a unit.
A 600mAh battery can typically still drive the same amount of current, just not as long as a 1800mAh batter.
When you have a 1A load on your battery the smaller one will drive that for 36 minutes while the larger one will last you 108 minutes.
Actually it does - just not as wattage but as current draw.
Multiply that with the 3.3V the system runs on to get the wattage.
When we allow for some safety margin with 10mA that would give you
3.3V * 0.010A = 0.033 VA = 0.033W
Or in or in terms of battery life time (for the sake of safety margin and ease of estamation take 3.7V instead of 3.3V)
600mAh / 10mA = 60h
(see how the units don’t just disappear)