This seems like such a trivial problem, but this code doesn’t work: if (s.Debug) { Serial.printlnf(“Starting UDP on Port %s .”, String(s.UDPPort, DEC); } The output is: [image] //In the class declaration for “s”… int UDPPort = 8023; The “s” variable is a class. The s.Debug is a bool an…

Output problem with printlnf

ninjatill April 13, 2018, 6:28pm 5

Thank you very much. Now I know.

Using Log.xxxx with formatting for IPAddress