String testString = “{“token”:123456789,“barcode”:[123456789,987654321],“quantity”:[1,5]}”;
char *testChar;
testChar <<<< testString; ???
Because i want to use JSMN Library to Json parser
JSON parser for Spark
Check out this post (Are string variables fully supported? [SOLVED]) for some examples. For more info on the toCharArray() method see this link: https://www.arduino.cc/en/Reference/StringToCharArray
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Syntax
string.toCharArray(buf, len)
String testString = “{“token”:123456789,“barcode”:[123456789,987654321],“quantity”:[1,5]}”;
char *testChar;
testString.toCharArray(testChar, ?) how I know that I have to put that value. ?
What exactly do you want to do with your string?
If you just want work with it as const char* or pass it to a function that expects a const char*, you could use string.c_str().
If you want to copy the string into a char array, you can use string.toCharArray() together with string.length().
But you’d need a char[] big enough to take all your copied characters. char* does not allocate any RAM to store the string to.
But you could also look at the docs
https://docs.particle.io/reference/firmware/photon/#string-class
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I just want to clear up one point. When you do char *testChar; above, that does not allocate any storage for the array of characters, so the next line which does essentially a memcpy, will clobber whatever comes after that pointer in memory.
Do this instead:
String testString = "{\"token\":123456789,\"barcode\":[123456789,987654321],\"quantity\":[1,5]}";
char testChar[65];
testString.toCharArray(testChar, 65);
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@bko, this can not be said often enough 
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Sorry I missed that in your response above! You were there before me again!
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Thanks! This worked perfectly for converting the time returned in string format via Particles Time.timeStr() function to a char array to display on an LCD screen that requires the data in Char format.
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